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23x^2+x-14/3=0
We multiply all the terms by the denominator
23x^2*3+x*3-14=0
Wy multiply elements
69x^2+3x-14=0
a = 69; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·69·(-14)
Δ = 3873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{3873}}{2*69}=\frac{-3-\sqrt{3873}}{138} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{3873}}{2*69}=\frac{-3+\sqrt{3873}}{138} $
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